Single transfer angle

Clamp-force transfer

Inputs

Actuator forceFKnown force at the stated linkage input.

Transfer angleθAngle between actuator direction and transferred force direction.

Transmission efficiencyη%User-entered multiplier for joint/friction losses, from 0 to 100.

Results

Transferred clamp force

1.9486

Ideal pivot-side component

1.25

Force transfer ratio

0.77942

—

Ftransfer = F·sin(θ)·η; Fpivot = F·|cos(θ)|

A first-pass number, not a code check, certification, or approval. Read the method and its limits below. What this is and is not.

Calculation snapshot

Clamp-force transfer

Formula version 1.0.0

Conditions

Actuator force	2.5
Transfer angle	60
Transmission efficiency	90

Calculated response

Transferred clamp force	1.9486 kN
Ideal pivot-side component	1.25 kN
Force transfer ratio	0.77942 —

Method

Ftransfer = F·sin(θ)·η · Fpivot = F·|cos(θ)|

Source

Pneumatic force-transfer reference: https://www.machinedesign.com/mechanical-motion-systems/article/21812520/matching-a-pneumatic-cylinders-output-to-the-application

Boundaries

Single force path
Planar transfer angle
User-entered transmission efficiency

This printout is a record of displayed inputs and deterministic formula output. It is not an approval, certification, or engineering conclusion.

Nearby: Trapezoidal motion · Reflected inertia · Pneumatic cylinder force · Lead-screw force & travel

Method

Formula, when it applies, and when it does not

Resolve the ideal force transferred through one linkage angle from a known cylinder or actuator force.

Ftransfer = F·sin(θ)·η; Fpivot = F·|cos(θ)|

When

Single force path
Planar transfer angle
User-entered transmission efficiency

Don’t

This is one planar transfer-angle relationship. It excludes linkage stiffness, bearing/friction variation, dynamics, buckling, contact geometry, retaining force under vibration, and machine-safety assessment.

Pneumatic force-transfer reference